CodeForces - 4A

Time limit：1000 ms
Memory limit：65536 kB

One hot summer day Pete and his friend Billy decided to buy a watermelon. They chose the biggest and the ripest one, in their opinion. After that the watermelon was weighed, and the scales showed w kilos. They rushed home, dying of thirst, and decided to divide the berry, however they faced a hard problem.

Pete and Billy are great fans of even numbers, that’s why they want to divide the watermelon in such a way that each of the two parts weighs even number of kilos, at the same time it is not obligatory that the parts are equal. The boys are extremely tired and want to start their meal as soon as possible, that’s why you should help them and find out, if they can divide the watermelon in the way they want. For sure, each of them should get a part of positive weight.

Input
The first (and the only) input line contains integer number w (1 ≤ w ≤ 100) — the weight of the watermelon bought by the boys.

Output
Print YES, if the boys can divide the watermelon into two parts, each of them weighing even number of kilos; and NO in the opposite case.

Examples
Input
8
Output
YES
Note

連結: CodeForces - 4A
問題描述：
分西瓜問題，要把西瓜分成兩份，這兩份不一定要等分，但這兩份的重量都要是偶數，而且他們都要有西瓜吃。

問題分析：
只要西瓜的重量為偶數，而且不為2就一定可以將西瓜分成兩個（一個是2，另一個是偶數）偶數重量的西瓜。

程式說明：
用if語句判斷w是否為偶數且不為2，如果是，YES；反之NO。注意判斷條件為邏輯等號

AC通過的C++程式如下：

#include<iostream>
using namespace std;
int main()
{
	int w;
	cin >> w;
	if (w == 2)
		cout << "NO" << endl;
	else if (w%2==0)
		cout << "yes" << endl;
	else cout << "NO";
	return 0;
}