Given a paragraph and a list of banned words, return the most frequent word that is not in the list of banned words.  It is guaranteed there is at least one word that isn't banned, and that the answer is unique.

Words in the list of banned words are given in lowercase, and free of punctuation.  Words in the paragraph are not case sensitive.  The answer is in lowercase.

Example:

Input: 
paragraph = "Bob hit a ball, the hit BALL flew far after it was hit."
banned = ["hit"]
Output: "ball"
Explanation: 
"hit" occurs 3 times, but it is a banned word.
"ball" occurs twice (and no other word does), so it is the most frequent non-banned word in the paragraph. 
Note that words in the paragraph are not case sensitive,
that punctuation is ignored (even if adjacent to words, such as "ball,"), 
and that "hit" isn't the answer even though it occurs more because it is banned.

Note:

• 1 <= paragraph.length <= 1000.
• 1 <= banned.length <= 100.
• 1 <= banned[i].length <= 10.
• The answer is unique, and written in lowercase (even if its occurrences in paragraph may have uppercase symbols, and even if it is a proper noun.)
• paragraph only consists of letters, spaces, or the punctuation symbols !?',;.
• There are no hyphens or hyphenated words.
• Words only consist of letters, never apostrophes or other punctuation symbols.

用split + 正則表示式把paragraph的單詞分離再轉成小寫，用hashmap儲存paragraph中的單詞，遍歷banned，在hashmap中去除相應key，最後找出hashmap中出現次數最多的key

注意正則表示式的用法：

[xyz]　　字符集，匹配包含的任一字元

+　　　  一次或多次匹配前面的字元或子表示式

time: O(P + B), space: O(P + B)　　-- P: length of paragraph, B: length of banned

class Solution {
    public String mostCommonWord(String paragraph, String[] banned) {
        String res = "";
        String[] words = paragraph.toLowerCase().split("[ !?',;.]+");
        HashMap<String, Integer> map = new HashMap<>();
        for(String word : words) {
            map.put(word, map.getOrDefault(word, 0) + 1);
        }
        for(String word : banned) {
            if(map.containsKey(word))
                map.remove(word);
        }
        
        for(String word : map.keySet()) {
            System.out.println(word);
            if(res == "" || map.get(word) > map.get(res))
                res = word;
        }
        return res;
    }
}