Comparable接口實現集合的排序
阿新 • • 發佈:2018-12-16
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1.讓需要排序的對象實現Comparable接口,並重寫compareTo方法
public class Student implements Comparable<Student> { //泛型為需要排序的對象
private int age;
private String name; private int score; public int getAge() { return age; } public void setAge(int age) { this.age = age; }public String getName() { return name; } public void setName(String name) { this.name = name; } public int getScore() { return score; } public void setScore(int score) { this.score = score; } public Student(int age, String name, int score) {super(); this.age = age; this.name = name; this.score = score; }
@Override public int compareTo(Student other) { //參數為需要排序的對象 return score-other.getScore(); //表示通過分數score字段進行排序 } }
2.構造需要排序的對象的集合,並調用Collections.sort()方法對集合中元素進行排序:
public class CompareTest {public static void main(String[] args) { Student s1 = new Student(16, "aa", 44); Student s2 = new Student(18, "bb", 88); Student s3 = new Student(17, "cc", 99); Student s4 = new Student(19, "dd", 66); List<Student> students = Arrays.asList(s1, s2, s3, s4); Collections.sort(students); //對students按score字段進行排序 for (Student student : students) { System.out.println(student.getScore()); } } }
註意:使用 Collections.sort(students);方法對集合對象進行排序時,集合中的對象必須實現Comparable接口,否則報錯
Comparable接口實現集合的排序