[leetcode]740. Delete and Earn

Analysis

唉 感覺應該GG了，還是好好刷題看論文吧—— [每天刷題並不難0.0]

Given an array nums of integers, you can perform operations on the array.
In each operation, you pick any nums[i] and delete it to earn nums[i] points. After, you must delete every element equal to nums[i] - 1 or nums[i] + 1.
You start with 0 points. Return the maximum number of points you can earn by applying such operations.

Implement

class Solution {
public:
    int deleteAndEarn(vector<int>& nums) {
        vector<int> n(10001, 0);
        for(int num:nums)
            n[num] += num;
        vector<
 
int> take(10001, 0);
        vector<int> skip(10001, 0);
        for(int i=1; i<10001; i++){
            take[i] = skip[i-1]+n[i];
            skip[i] = max(skip[i-1], take[i-1]);
        }
        return max(take[10000], skip[10000]);
    }
};