Python生成目錄樹
阿新 • • 發佈:2018-12-17
# -*- coding: utf-8 -*- import sys from pathlib import Path class DirectionTree(object): """生成目錄樹 @ pathname: 目標目錄 @ filename: 要儲存成檔案的名稱 """ def __init__(self, pathname='.', filename='tree.txt'): super(DirectionTree, self).__init__() self.pathname = Path(pathname) self.filename = filename self.tree = '' def set_path(self, pathname): self.pathname = Path(pathname) def set_filename(self, filename): self.filename = filename def generate_tree(self, n=0): if self.pathname.is_file(): self.tree += ' |' * n + '-' * 4 + self.pathname.name + '\n' elif self.pathname.is_dir(): self.tree += ' |' * n + '-' * 4 + \ str(self.pathname.relative_to(self.pathname.parent)) + '\\' + '\n' for cp in self.pathname.iterdir(): self.pathname = Path(cp) self.generate_tree(n + 1) def save_file(self): with open(self.filename, 'w', encoding='utf-8') as f: f.write(self.tree) if __name__ == '__main__': dirtree = DirectionTree() # 命令引數個數為1,生成當前目錄的目錄樹 if len(sys.argv) == 1: dirtree.set_path(Path.cwd()) dirtree.generate_tree() print(dirtree.tree) # 命令引數個數為2並且目錄存在存在 elif len(sys.argv) == 2 and Path(sys.argv[1]).exists(): dirtree.set_path(sys.argv[1]) dirtree.generate_tree() print(dirtree.tree) # 命令引數個數為3並且目錄存在存在 elif len(sys.argv) == 3 and Path(sys.argv[1]).exists(): dirtree.set_path(sys.argv[1]) dirtree.generate_tree() dirtree.set_filename(sys.argv[2]) dirtree.save_file() else: # 引數個數太多,無法解析 print('命令列引數太多,請檢查!')
可以使用以下三條命令進行測試: python dirtree.py :列印當前目錄的目錄樹; python dirtree.py E:\Programming\Python\applications:列印指定目錄的目錄樹; python dirtree.py E:\Programming\Python\applications dirtree.txt:列印指定目錄的目錄樹並儲存成檔案。