FastJson反序列化為什麼用TypeReference
阿新 • • 發佈:2018-12-19
泛型序列化非TypeReference code:
public static void main(String[] args) { Map<String, Person> map = new HashMap<>(16); map.put("one", new Person("zhangsan")); map.put("two", new Person("lisi")); String jsonStr = JSON.toJSONString(map); byte[] bytes = jsonStr.getBytes(); String json = new String(bytes); Map<String, Person> res = JSON.parseObject(json, Map.class); System.out.println(res.get("one")); System.out.println(res.get("one").getName()); }
輸出:
Exception in thread "main" java.lang.reflect.InvocationTargetException at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) at java.lang.reflect.Method.invoke(Method.java:498) at com.intellij.rt.execution.CommandLineWrapper.main(CommandLineWrapper.java:67) Caused by: java.lang.ClassCastException: com.alibaba.fastjson.JSONObject cannot be cast to subtitle.io.Person at subtitle.io.MyMain.main(MyMain.java:48) ... 5 more {"name":"zhangsan"}
泛型序列化TypeReference code:
public static void main(String[] args) { Map<String, Person> map = new HashMap<>(16); map.put("one", new Person("zhangsan")); map.put("two", new Person("lisi")); String jsonStr = JSON.toJSONString(map); byte[] bytes = jsonStr.getBytes(); String json = new String(bytes); Map<String, Person> res = JSON.parseObject(json, new TypeReference<Map<String, Person>>(){}); System.out.println(res.get("one")); System.out.println(res.get("one").getName()); }
輸出:
Person{name='zhangsan'}
zhangsan
報錯原因: 反序列化時候,雖然新增Map.class,但是沒有辦法指定Person型別,導致反序列化後的物件為Map<String, Map<String, String>>,而不是Map<String, Person>,所以針對泛型的反序列化,需要使用TypeReference