不會寫。。。 記住板子吧。。

#include<stdio.h>
#include<iostream>
#include<math.h>
#include<assert.h>
using namespace std;
typedef long long LL;

typedef unsigned long long u64;
typedef __int128_t i128;
typedef __uint128_t u128;

struct Mod64 {
	Mod64():n_(0) {}
	Mod64(u64 n):n_(init(n)) {}
	static u64 init(u64 w) { return reduce(u128(w) * r2); }
	static void set_mod(u64 m) {
		mod=m; assert(mod&1);
		inv=m;
		for(int i=0;i<5;i++)
			inv*=2-inv*m;
		r2=-u128(m)%m;
	}
	static u64 reduce(u128 x) {
		u64 y=u64(x>>64)-u64((u128(u64(x)*inv)*mod)>>64);
		return LL(y)<0?y+mod:y;
	}
	Mod64& operator += (Mod64 rhs) { n_+=rhs.n_-mod; if (LL(n_)<0) n_+=mod; return *this; }
	Mod64 operator + (Mod64 rhs) const { return Mod64(*this)+=rhs; }
	Mod64& operator -= (Mod64 rhs) { n_-=rhs.n_; if (LL(n_)<0) n_+=mod; return *this; }
	Mod64 operator - (Mod64 rhs) const { return Mod64(*this)-=rhs; }
	Mod64& operator *= (Mod64 rhs) { n_=reduce(u128(n_)*rhs.n_); return *this; }
	Mod64 operator * (Mod64 rhs) const { return Mod64(*this)*=rhs; }
	u64 get() const { return reduce(n_); }
	static u64 mod,inv,r2;
	u64 n_;
};
u64 Mod64::mod,Mod64::inv,Mod64::r2;

//a*b%p 的防止超ll限度的寫法
u64 pmod(u64 a,u64 b,u64 p) {
	u64 d=(u64)floor(a*(long double)b/p+0.5);
	LL ret=a*b-d*p;
	if (ret<0) ret+=p;
	return ret;
}

//Mod64::set_mod(M);	//模設定
//Mod64 a(_a);	//定義，初始化
//_a = a.get();	//轉數值
//用%llu輸入輸出
//定義 u64;

int main()
{
	int T;
	scanf("%d",&T);
	while(T--){
		u64 a0_,a1_,m0_,m1_,c_,M_;
		int k;
		scanf("%llu%llu%llu%llu%llu%llu%d",&a0_,&a1_,&m0_,&m1_,&c_,&M_,&k);
		Mod64::set_mod(M_);
		Mod64 a0(a0_),a1(a1_),m0(m0_),m1(m1_),c(c_),M(M_),ans(1),x(0);
		ans=ans*a1*a0;
		for(int i=2;i<=k;i++){
			x=m0*a1+m1*a0+c;
			ans=ans*x;
			a0=a1;
			a1=x;
		}
		printf("%llu\n",ans.get());
	}
}