首先是找到一個可以線上傳引數的api

public class GpsToBaidu {

    public static JSONObject GpsToBaiDu(String latitude, String longitude) {
        //URL
        String requestUrl = "http://map.yanue.net/gpsapi.php?";
        //請求引數
        String params = "lat=" + latitude + "&lng=" + longitude;
        //傳送請求
        String data = HttpUtils.get(requestUrl + params);
        //解析相應內容（轉換成json物件）
        JSONObject json = JSONObject.fromObject(data);
        JSONObject jsons = JSONObject.fromObject(String.valueOf(json.get("baidu")));
        return jsons;
    }
}
 

 呼叫的方法

 JSONObject lacation = GpsToBaidu.GpsToBaiDu(latitude, longitude);
        System.out.println(lacation);
        latitude = String.valueOf(lacation.get("lat"));
        longitude = String.valueOf(lacation.get("lng"));

搞定，這是呼叫一位仁兄現成的api，下面是離線自己寫的

/**
 * Author： 哈哈哈
 * Time: 2018/11/5
 * 介紹：
 */
public class Test {
    static double pi = 3.14159265358979324;
    static double a = 6378245.0;
    static double ee = 0.00669342162296594323;
    public final static double x_pi = 3.14159265358979324 * 3000.0 / 180.0;

    public static double[] wgs2bd(double lat, double lon) {
        double[] wgs2gcj = wgs2gcj(lat, lon);
        double[] gcj2bd = gcj2bd(wgs2gcj[0], wgs2gcj[1]);
//        System.out.println(gcj2bd);
        return gcj2bd;
    }

    public static double[] gcj2bd(double lat, double lon) {
        double x = lon, y = lat;
        double z = Math.sqrt(x * x + y * y) + 0.00002 * Math.sin(y * x_pi);
        double theta = Math.atan2(y, x) + 0.000003 * Math.cos(x * x_pi);
        double bd_lon = z * Math.cos(theta) + 0.0065;
        double bd_lat = z * Math.sin(theta) + 0.006;
        return new double[] { bd_lat, bd_lon };
    }

    public static double[] bd2gcj(double lat, double lon) {
        double x = lon - 0.0065, y = lat - 0.006;
        double z = Math.sqrt(x * x + y * y) - 0.00002 * Math.sin(y * x_pi);
        double theta = Math.atan2(y, x) - 0.000003 * Math.cos(x * x_pi);
        double gg_lon = z * Math.cos(theta);
        double gg_lat = z * Math.sin(theta);
        return new double[] { gg_lat, gg_lon };
    }

    public static double[] wgs2gcj(double lat, double lon) {
        double dLat = transformLat(lon - 105.0, lat - 35.0);
        double dLon = transformLon(lon - 105.0, lat - 35.0);
        double radLat = lat / 180.0 * pi;
        double magic = Math.sin(radLat);
        magic = 1 - ee * magic * magic;
        double sqrtMagic = Math.sqrt(magic);
        dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);
        dLon = (dLon * 180.0) / (a / sqrtMagic * Math.cos(radLat) * pi);
        double mgLat = lat + dLat;
        double mgLon = lon + dLon;
        double[] loc = { mgLat, mgLon };
        return loc;
    }

    private static double transformLat(double lat, double lon) {
        double ret = -100.0 + 2.0 * lat + 3.0 * lon + 0.2 * lon * lon + 0.1 * lat * lon + 0.2 * Math.sqrt(Math.abs(lat));
        ret += (20.0 * Math.sin(6.0 * lat * pi) + 20.0 * Math.sin(2.0 * lat * pi)) * 2.0 / 3.0;
        ret += (20.0 * Math.sin(lon * pi) + 40.0 * Math.sin(lon / 3.0 * pi)) * 2.0 / 3.0;
        ret += (160.0 * Math.sin(lon / 12.0 * pi) + 320 * Math.sin(lon * pi  / 30.0)) * 2.0 / 3.0;
        return ret;
    }

    private static double transformLon(double lat, double lon) {
        double ret = 300.0 + lat + 2.0 * lon + 0.1 * lat * lat + 0.1 * lat * lon + 0.1 * Math.sqrt(Math.abs(lat));
        ret += (20.0 * Math.sin(6.0 * lat * pi) + 20.0 * Math.sin(2.0 * lat * pi)) * 2.0 / 3.0;
        ret += (20.0 * Math.sin(lat * pi) + 40.0 * Math.sin(lat / 3.0 * pi)) * 2.0 / 3.0;
        ret += (150.0 * Math.sin(lat / 12.0 * pi) + 300.0 * Math.sin(lat / 30.0 * pi)) * 2.0 / 3.0;
        return ret;
    }

}
 

搞定，呼叫方法

  double[] tt = Test.wgs2bd(Double.parseDouble(latitude), Double.parseDouble(longitude));

        System.out.println(tt[0]);
        System.out.println(tt[1]);