python leetcode 287. Find the Duplicate Number
class Solution:
def findDuplicate(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
for i in range(len(nums)):
index = abs(nums[i])-1
if nums[index] < 0:
return abs(nums[i])
else:
nums[ index] = -nums[index]
相關推薦
python leetcode 287. Find the Duplicate Number
class Solution: def findDuplicate(self, nums): """ :type nums: List[int] :rtype: int """ for i in rang
LeetCode 287. Find the Duplicate Number (找到重復的數字)
ant pre ast web integer lan algorithm xtra 理論 Given an array nums containing n + 1 integers where each integer is between 1 and n (inclus
LeetCode 287. Find the Duplicate Number
find 由於 ray all turn num pre n-1 DDU 解法一: 類似 LeetCode 442. Find All Duplicates in an Array,由於元素是1~n,因此每個元素的值-1(映射到0~n-1)就可以直接當做下標。 cl
[LeetCode] 287. Find the Duplicate Number 尋找重復數
blank arc modify ini lba read href use rep Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive
[LeetCode] 287. Find the Duplicate Number
etc int 一個數 空間 ont slow i++ for clu Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prov
[leetcode]287. Find the Duplicate Number
[leetcode]287. Find the Duplicate Number Analysis fighting!!!—— [每天刷題並不難0.0] Given an array nums containing n + 1 integers where e
leetcode 287. Find the Duplicate Number(二分/快慢指標)
1.二分方法 因為數字是1~n,所以我們可以根據小於mid的數目來判斷重複的數字是在左邊還是右邊 class Solution { public: int findDuplicate(vector<int>& nums) { int lef
LeetCode 287 Find the Duplicate Number
287. Find the Duplicate Number Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove tha
LeetCode---287. Find the Duplicate Number
題目 給出一個含有n+1個元素的陣列,裡面的元素值在1到n的範圍內,找出重複的數字,假設只存在一個重複的數字,該數字的次數可能出現多次。 Python題解 class Solution:
leetcode 287 Find the Duplicate Number尋找重復數
bre i++ The () stl容器 insert cat != bsp 這道題用STL容器就很好寫了,可以用set也可以用map, 用unordered_map的C++代碼如下: 1 class Solution { 2 public: 3 int
leetcode 217. Contains Duplicate 287. Find the Duplicate Number
DDU dup detail The .html cto false urn .net 217. Contains Duplicate 後面3個題都是限制在1~n的 class Solution { public: bool containsDuplicate(
LeetCode:287. Find the Duplicate Number(找出重複的數)
Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one
【LeetCode & 劍指offer刷題】陣列題5:3 陣列中重複的數字(287. Find the Duplicate Number)
【LeetCode & 劍指offer 刷題筆記】目錄(持續更新中...) 287 . Find the Duplicate Number Given an array nums
【LeetCode】287. Find the Duplicate Number
287. Find the Duplicate Number Description: Given an array nums containing n + 1 integers where each integer is between 1 and n (in
【Leetcode】287. Find the Duplicate Number(快慢指標+連結串列找環的起點)
Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate
287. Find the Duplicate Number
you 原理 mat 行動 row dup pac dex strong Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), pro
287. Find the Duplicate Number 尋找重複數
Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate element
LeetCode 287.尋找重複數 Find the Duplicate Number
題目連結 一個長度是n+1的陣列,出現的整數都在1到n之間(包括1和n),已知有一個重複出現的整數。求該整數。 要求: 1.不能更改原陣列 2.空間複雜度O(1) 3.時間複雜度小於O(n²) 4.陣列中只有一個重複的數字,但它可能不止重複出現1次。
LeetCode-Find the Duplicate Number
一、Description 題目描述: 給定n + 1個數字,這些數字的範圍在1 - n之間,在這些數字中有一個出現不止一次的數字,找出這個數字。 要求用O(1)的空間和少於O(n^2)的時間複雜度。 二、Analyzation 遍歷這個陣列,對於每個數字x,nums[x
[LeetCode] Find the Duplicate Number 尋找重複數
Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Ass