Leetcode-by python3
阿新 • • 發佈:2018-12-23
#買賣股票的最佳時機 III class Solution: def maxProfit(self, prices): n = len(prices) if n <= 1: return 0 p1 = [0] * n #p1=[0,0,0,0,...,0] p2 = [0] * n minV = prices[0] for i in range(1,n): minV = min(minV, prices[i]) # Find low and buy low p1[i] = max(p1[i - 1], prices[i] - minV) maxV = prices[-1] for i in range(n-2, -1, -1): maxV = max(maxV, prices[i]) # Find high and sell high p2[i] = max(p2[i + 1], maxV - prices[i]) res = 0 for i in range(n): res = max(res, p1[i] + p2[i]) return res