HDU 2899 二分答案
阿新 • • 發佈:2018-12-24
Strange fuction
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 6881 Accepted Submission(s): 4814
Problem Description Now, here is a fuction:
F(x) = 6 * x^7+8*x^6+7*x^3+5*x^2-y*x (0 <= x <=100)
Can you find the minimum value when x is between 0 and 100.
Input The first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines follow, each line has only one real numbers Y.(0 < Y <1e10)
Output Just the minimum value (accurate up to 4 decimal places),when x is between 0 and 100.
Sample Input 2 100 200
Sample Output -74.4291 -178.8534
#include <cstdio> #include <cstdlib> #include <iostream> #include <set> #include <cmath> #include <string> #include <cstring> #include <algorithm> #include <cctype> #include <queue> using namespace std; typedef long long ll; double x,y; double val(double x) { return 6*x*x*x*x*x*x*x+8*x*x*x*x*x*x+7*x*x*x+5*x*x-y*x; } double solve(double l,double r) { double eps = 1e-7; while(l + eps < r)//確定一個終止查詢的條件 { double lmid=l+(r-l)/3,rmid=r-(r-l)/3; if(val(lmid)<val(rmid)) r=rmid; else l=lmid; } return val(l); } int main() { ll t; cin>>t; while(t--) { cin>>y; printf("%.4f\n", solve(0,100.0)); } }