Newtonsoft.Json反序列化(Deserialize)報錯問題
阿新 • • 發佈:2018-12-25
資料 regex char 分隔符 build doc inf clas har
使用Newtonsoft.Json反序列化收到的字串為JObject或其它支持的數據模型,有時錯誤,提示如下:
Bad JSON escape sequence: \c. Path ‘idno‘, line 5, position 34.
甚納悶之。遂搜索資料,略有小獲,其非法分界符所致。合法的分隔符為:
以此為依據,對字串做正則替換,問題解決,錄代碼以記之。
static void Main(string[] args) { string s = @" { ""name"": ""王艷"", ""sex"": ""女"", ""idno"": ""34*****\c0"", ""addr"": ""安徽省"", ""telephone"": ""no number"", ""thumbnail"": ""e:\docs\person\thumbnail\wy.jpg"", ""Age"": 27, ""DeptName"": ""姚江\R中心"" }"; //\加bfrnt\/‘"為合法分隔符,其它不是,替換 string pattern = @"(\\[^bfrnt\\/‘\""])"; s = Regex.Replace(s, pattern, "\\$1"); var jo = JsonConvert.DeserializeObject<JObject>(s); Console.WriteLine(jo.ToString()); Console.ReadLine(); }
結果如圖:
參考資料:
How to escape special characters in building a JSON string? - Stack Overflow
Bad JSON escape sequence: \l. Path 'Transforms[0].Path', line 3, position 45. · Issue #343 · mmanela/chutzpah
Newtonsoft.Json反序列化(Deserialize)報錯問題