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[CareerCup] 9.1 Climbing Staircase 爬樓梯

9.1 A child is running up a staircase with n steps, and can hop either 1 step, 2 steps, or 3 steps at a time. Implement a method to count how many possible ways the child can run up the stairs.

class Solution {
public:
    int countWays(int n) {
        vector<int> res(n + 1, 1);
        
for (int i = 2; i <= n; ++i) { res[i] = res[i - 1] + res[i - 2]; } return res.back(); } };