jquery獲取當前tomcat目錄
阿新 • • 發佈:2018-12-30
- //獲取url地址根目錄 當前taomcat下路徑
- function getRootPath()
- {
- var pathName = window.location.pathname.substring(1);
- var webName = pathName == '' ? '' : pathName.substring(0, pathName.indexOf('/'));
- return window.location.protocol + '//' + window.location.host + '/'+ webName;
- }
[javascript]
- 得到當前目錄後並返回上一層目錄
- function getImgPath()
- {
- var pathName = window.location.pathname.substring(1);
- var webName = pathName == '' ? '' : pathName.substring(0, pathName.indexOf('/'));
- var urlpath= window.location.protocol + '//' + window.location.host + '/'+ webName;
-
return
- }
在做一個專案時,載入當前圖片資訊,路徑每每都不正確,最後得到此結論。
附上常用的js獲取Path:- //js獲取專案根路徑,如: http://localhost:8083/uimcardprj
- function getRootPath(){
- //獲取當前網址,如: http://localhost:8083/uimcardprj/share/meun.jsp
- var curWwwPath=window.document.location.href;
-
//獲取主機地址之後的目錄,如: uimcardprj/share/meun.jsp
- var pathName=window.document.location.pathname;
- var pos=curWwwPath.indexOf(pathName);
- //獲取主機地址,如: http://localhost:8083
- var localhostPaht=curWwwPath.substring(0,pos);
- //獲取帶"/"的專案名,如:/uimcardprj
- var projectName=pathName.substring(0,pathName.substr(1).indexOf('/')+1);
- return(localhostPaht+projectName);
- }