#include <stdio.h>
#include <stdbool.h>
/*
    功能：根據當天日期輸出明天的日期
    時間：2018-06-05
     //此程式無輸入錯誤檢測
*/ 

//定義一個日期型別 形如2018-06-05 
struct date{
    int year;
    int month;
    int day;
};

//判斷某年是否為閏年 
bool isLeap(struct date d);
//返回某月的總天數 
int numberOfDays(struct date d);

int main(int argc,char const
 
 *argv[])
{
    struct date today, tomorrow;
    printf("輸入今天的日期:(year mm dd)");
    scanf("%i %i %i",&today.year,&today.month,&today.day);

    //如果當天不是本月的最後一天 
    if(today.day != numberOfDays(today) ){
        tomorrow.day =  today.day + 1;
        tomorrow.month = today.month;
        tomorrow.year = today.year;
    }else
 
 if( today.month == 12 ){
        //如果當天是今年的最後一天
        tomorrow.day = 1;
        tomorrow.month = 1;
        tomorrow.year = today.year + 1;
    }else{
        tomorrow.day = 1;
        tomorrow.month = today.month + 1;
        tomorrow.year = today.year; 
    }    

    printf("明天的日期是: %i-%i-%i",tomorrow.year,tomorrow.month,tomorrow.day);

    return
 
 0; 
}

int numberOfDays(struct date d)
{
    int days;
    //每個月份的天數 
    const int daysPerMonth[13] = {0,31,28,31,30,31,30,31,31,30,31,30,31};
    if( 2 == d.month  && isLeap(d) ){
        days = 29;
    }else{
        days = daysPerMonth[d.month];
    }
    return days;
}

bool isLeap(struct date d)
{
    bool leap = false;
    if( (d.year % 4 == 0 && d.year % 100 != 0) || d.year % 400 == 0 ){
        leap = true;
    }
    return leap;
}