1. 程式人生 > >ceph 獲取每個osd上pg的數量

ceph 獲取每個osd上pg的數量

Get the PG distribution per osd in command line :

ceph pg dump | awk '
 /^pg_stat/ { col=1; while($col!="up") {col++}; col++ }
 /^[0-9a-f]+\.[0-9a-f]+/ { match($0,/^[0-9a-f]+/); pool=substr($0, RSTART, RLENGTH); poollist[pool]=0;
 up=$col; i=0; RSTART=0; RLENGTH=0; delete osds; while(match(up,/[0-9]+/)>0) { osds[++i]=substr(up,RSTART,RLENGTH); up = substr(up, RSTART+RLENGTH) }
 for(i in osds) {array[osds[i],pool]++; osdlist[osds[i]];}
}
END {
 printf("\n");
 printf("pool :\t"); for (i in poollist) printf("%s\t",i); printf("| SUM \n");
 for (i in poollist) printf("--------"); printf("----------------\n");
 for (i in osdlist) { printf("osd.%i\t", i); sum=0;
 for (j in poollist) { printf("%i\t", array[i,j]); sum+=array[i,j]; poollist[j]+=array[i,j] }; printf("| %i\n",sum) }
 for (i in poollist) printf("--------"); printf("----------------\n");
 printf("SUM :\t"); for (i in poollist) printf("%s\t",poollist[i]); printf("|\n");
}'

結果:
dumped all in format plain
 
pool :  0   1   | SUM 
--------------------------------
osd.0   64  35  | 99
osd.1   64  47  | 111
osd.2   64  46  | 110
--------------------------------
SUM :   192 128 |