[LeetCode] 079: Regular Expression Matching
阿新 • • 發佈:2018-12-31
[Problem]
[Solution]
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Implement regular expression matching with support for '.'
and '*'
.
'.' Matches any single character. '*' Matches zero or more of the preceding element. The matching should cover the entire input string (not partial). The function prototype should be: bool isMatch(const char *s, const char *p) Some examples: isMatch("aa","a") → false isMatch("aa","aa") → true isMatch("aaa","aa") → false isMatch("aa", "a*") → true isMatch("aa", ".*") → true isMatch("ab", ".*") → true isMatch("aab", "c*a*b") → true
[Solution]
class Solution {
public:
bool isMatch(const char *s, const char *p) {
// Note: The Solution object is instantiated only once and is reused by each test case.
if(s == NULL || p == NULL)return false;
// special cases
if(*p == '\0')return *s == '\0';
// the next character is not '*'
if(*(p+1) != '*'){
return (*s == *p || (*p == '.' && *s != '\0')) && isMatch(s+1, p+1);
}
// the next character is '*'
while(*s != '\0' && (*s == *p || *p == '.')){
if(isMatch(s, p+2)){
return true;
}
s++;
}
return isMatch(s, p+2);
}
};