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[LeetCode] 079: Regular Expression Matching

[Problem]

Implement regular expression matching with support for '.' and '*'.

'.' Matches any single character.
'*' Matches zero or more of the preceding element.

The matching should cover the entire input string (not partial).

The function prototype should be:
bool isMatch(const char *s, const char *p)

Some examples:
isMatch("aa","a") → false
isMatch("aa","aa") → true
isMatch("aaa","aa") → false
isMatch("aa", "a*") → true
isMatch("aa", ".*") → true
isMatch("ab", ".*") → true
isMatch("aab", "c*a*b") → true

[Solution]
class Solution {
public:
bool isMatch(const char *s, const char *p) {
// Note: The Solution object is instantiated only once and is reused by each test case.
if(s == NULL || p == NULL)return false;

// special cases
if(*p == '\0')return *s == '\0';

// the next character is not '*'
if(*(p+1) != '*'){
return (*s == *p || (*p == '.' && *s != '\0')) && isMatch(s+1, p+1);
}

// the next character is '*'
while(*s != '\0' && (*s == *p || *p == '.')){
if(isMatch(s, p+2)){
return true;
}
s++;
}
return isMatch(s, p+2);
}
};
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