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python快排:一個pythonic的寫法

def quicksort(arr):
    if len(arr) <= 1:
        return arr
    pivot = arr[len(arr) // 2]
    left = [x for x in arr if x < pivot]
    middle = [x for x in arr if x == pivot]
    right = [x for x in arr if x > pivot]
    return quicksort(left) + middle + quicksort(right)

print(quicksort([3
,6,8,10,1,2,1])) # Prints "[1, 1, 2, 3, 6, 8, 10]"