form表單的兩種提交方式,submit和button的用法
方法一:
在jsp的前端頁面的頭部插入一個js方法:
function checkUser(){
var result = document.getElementById("userid").value;
var password = document.getElementById("userpassid").value;
if(result == "" ){
alert("使用者名稱不能為空");
return false;
}
if(password == "" ){
alert("密碼不能為空");
return false;
}else{
return true;
}
}
在form表單裡寫成這樣:
<form id="formid" name= "myform" method = 'post' action = 'user_login_submit.action'
onsubmit = "return checkUser();" >
<table width="100%" border="0">
<tr>
<td width="60" height="40" align="right">使用者名稱 </td>
<td><input type="text" value="" class="text2" name = "username" id = "userid"/></td>
</tr>
<tr>
<td width="60" height="40" align="right">密 碼 </td>
<td><input type="password" value="" class="text2" name = "userpass" id = "userpassid"/></td>
</tr>
<tr>
<td width="60" height="40" align="right"> </td>
<td><div class="c4">
<input type="submit" value="" class="btn2" />
方法二:
function checkUser(){
var result = document.getElementById("userid").value;
var password = document.getElementById("passid").value;
if(result == "" ){
alert("使用者名稱不能為空");
return false;
}
if(password == "" ){
alert("密碼不能為空");
return false;
}
document.getElementById("formid").submit();
}
form表格的寫法,需要寫id
<form id="formid" method = 'post' action = 'user_login_submit.action' >
button按鈕的寫法如下:
<input type="button" value="" class="btn2" onclick = "checkUser();" />