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889. Construct Binary Tree from Preorder and Postorder Traversal - Medium

Return any binary tree that matches the given preorder and postorder traversals.

Values in the traversals pre and post are distinct positive integers.

 

Example 1:

Input: pre = [1,2,4,5,3,6,7], post = [4,5,2,6,7,3,1]
Output: [1,2,3,4,5,6,7]

 

Note:

  • 1 <= pre.length == post.length <= 30
  • pre[] and post[] are both permutations of 1, 2, ..., pre.length.
  • It is guaranteed an answer exists. If there exists multiple answers, you can return any of them.

 

time: O(nlogn) ~ O(n^2), space: O(height)

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 
*/ class Solution { public TreeNode constructFromPrePost(int[] pre, int[] post) { return buildTree(pre, 0, pre.length - 1, post, 0, post.length - 1); } public TreeNode buildTree(int[] pre, int pre_start, int pre_end, int[] post, int post_start, int post_end) { if(pre_start > pre_end || post_start > post_end) {
return null; } TreeNode root = new TreeNode(pre[pre_start]); if(pre_start + 1 > pre_end) { return root; } int idx = 0; for(int i = post_start; i <= post_end; i++) { if(post[i] == pre[pre_start + 1]) { idx = i; break; } } root.left = buildTree(pre, pre_start + 1, pre_start + idx - post_start + 1, post, post_start, idx); root.right = buildTree(pre, pre_start + idx - post_start + 2, pre_end, post, idx + 1, post_end - 1); return root; } }