檢視Oracle最耗時的SQL
有很多種方法可以用來找出哪些SQL語句需要優化,但是很久以來,最簡單的方法都是分析儲存在V$SQL檢視中的快取的SQL資訊。通過V$SQL檢視,可以確定具有高消耗時間、CUP和IO讀取的SQL語句。
1.檢視總消耗時間最多的前10條SQL語句
select *
from (select v.sql_id,
v.child_number,
v.sql_text,
last_load_time,
v.PARSING_USER_ID,
ROUND(v.ELAPSED_TIME / 1000000 / (CASE
WHEN (EXECUTIONS = 0 OR NVL(EXECUTIONS, 1 ) = 1) THEN
1
ELSE
EXECUTIONS
END),
2) "執行時間'S'",
v.SQL_FULLTEXT,
v.cpu_time,
v.disk_reads,
rank() over(order by v.elapsed_time desc) elapsed_rank
from v$sql v ) a
where elapsed_rank <= 100 and last_load_time > to_char(sysdate - 1/24, 'YYYY-MM-DD/HH:MI:SS') order by "執行時間'S'" desc
查詢最近一小時內最慢的SQL:
select executions, cpu_time/1e6 as cpu_sec, elapsed_time/1e6 as elapsed_sec, round(elapsed_time/sqrt(executions)) as important, v.*
from v$sql v
where executions > 10 and last_load_time > to_char(sysdate - 1/24, 'YYYY-MM-DD/HH:MI:SS')
order by important desc
2.檢視CPU消耗時間最多的前10條SQL語句
select *
from (select v.sql_id,
v.child_number,
v.sql_text,
v.elapsed_time,
v.cpu_time,
v.disk_reads,
rank() over(order by v.cpu_time desc) elapsed_rank
from v$sql v) a
where elapsed_rank <= 10;
3.檢視消耗磁碟讀取最多的前10條SQL語句
select *
from (select v.sql_id,
v.child_number,
v.sql_text,
v.elapsed_time,
v.cpu_time,
v.disk_reads,
rank() over(order by v.disk_reads desc) elapsed_rank
from v$sql v) a
where elapsed_rank <= 10;
一、查詢執行最慢的sql
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select
*
from ( select sa.SQL_TEXT,
sa.SQL_FULLTEXT,
sa.EXECUTIONS "執行次數" ,
round(sa.ELAPSED_TIME / 1000000, 2) "總執行時間" ,
round(sa.ELAPSED_TIME / 1000000 / sa.EXECUTIONS, 2) "平均執行時間" ,
sa.COMMAND_TYPE,
sa.PARSING_USER_ID "使用者ID" ,
u.username "使用者名稱" ,
sa.HASH_VALUE
from v$sqlarea sa
left join all_users
u
on sa.PARSING_USER_ID = u.user_id
where sa.EXECUTIONS > 0
order by (sa.ELAPSED_TIME / sa.EXECUTIONS) desc )
where rownum <= 50;
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二、查詢次數最多的 sql
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select
*
from ( select s.SQL_TEXT,
s.EXECUTIONS "執行次數" ,
s.PARSING_USER_ID "使用者名稱" ,
rank() over( order by EXECUTIONS
desc ) EXEC_RANK
from v$sql s
left join all_users u
on u.USER_ID = s.PARSING_USER_ID) t
where exec_rank <= 100;
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