[BZOJ2456/ZOJ2132]mode/The Most Frequent Number
題目連結:
日常鍛鍊思維(雖然這題很簡單就是了)
因為眾數個數超過\(\frac n2\),那麼若數列中有兩個數不相同就消去,最後眾數一定可以抵消掉所有其他數。
然後模擬即可。
#include <cstdio> int n,a,c,x; //a 當前數,c 當前數個數 int main() { scanf("%d",&n); while(n--) { scanf("%d",&x); if(!c)a=x,c=1;//新數 else if(a==x)++c;//相同,個數+1 else --c;//不相同,抵消 } printf("%d\n",a); return 0; }
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