替換特殊字元：將‘\'’替換為空格

def check_quoto(str, n):
    for i in range(len(str) - int(n)):
	npos_q = -1
	npos_b = -1
        while keys[i + int(n)].count('\'') > 0:
            npos_q = str[i + int(n)].find('\'')
            npos_b = str[i + int(n)].find(' ')
            keys[i + int(n)] = replaceString(str[i + int(n)], npos_q, ' ')
        if npos_q >= 0 or npos_b > 0:
            keys[i + int(n)] = '\'' + keys[i + int(n)] + '\''
    return keys
 

def replaceString(string, num, replace):
    string2 = ''
    for i in range(len(string)):
        if i == num:
            string2 += replace
        else:
            string2 += string[i]
    return string2