java list轉String,list轉map,String陣列轉list,帶逗號String轉list
阿新 • • 發佈:2019-01-05
專案中經常會遇到list轉String,list轉map,String轉list等情況,特在這裡記錄一下。
1.list轉String
將List集合轉化為用符號隔開的String字串,只要用StringUtils中的join就行。
String listToString= org.apache.commons.lang3.StringUtils.join(list, ",")
2.list轉map
我們會常遇到將一個list按某個欄位作為key轉為map,如下面,按年齡轉map,傳統方法是直接做迴圈:
Map<Integer, List<Person>> map = new HashMap<>();
List<Person> list = new ArrayList<>();
Person person1 = new Person(20, "張三","男");
Person person2 = new Person(21, "李四","男");
Person person3 = new Person(32, "王五","男");
Person person4 = new Person(21, "劉六","男");
Person person5 = new Person(20, "田七","男");
Person person6 = new Person(32, "王八","男");
Person person7 = new Person(21, "阿狗","男");
Person person8 = new Person(20, "阿十","男");
list.add(person1);
list.add(person2);
list.add(person3);
list.add(person4);
list.add(person5);
list .add(person6);
list.add(person7);
list.add(person8);
for (Person person : list) {
map.put(person.getAge(), new ArrayList<>());
}
Map<Integer, List<Person>> map1 = new HashMap<>();
for (Map.Entry<Integer, List<Person>> entry : map.entrySet()) {
List<Person> userList = new ArrayList<>();
for (Person person : list) {
if (entry.getKey() == person.getAge()) {
userList.add(person);
}
}
map.put(entry.getKey(), userList);
userList = null;
}
}
但我還是推薦用Java8 的Stream來做,特別簡單:
Map<Integer,List<Person>> map2=list.parallelStream().collect(Collectors.groupingBy(Person::getAge));
就一句話的事。Java8的Stream對集合的操作都挺好用的,下次抽時間來分享一下。
3.String陣列轉list
定義一個String陣列,用Arrays.asList轉:
String[] string = {"aa","bb","cc"};
List<String> stringToList= Arrays.asList(string);
4.帶逗號String轉list
1.轉Integer型別list
String IntegerType="1,2,3";
List<Integer> IntegerResult = Arrays.asList(StringType.split(",")).stream().map(s ->Integer.parseInt(s.trim())).collect(Collectors.toList());
2.轉String型別的list
String StringType="a,b,c";
List<String> StringResult = Arrays.asList(StringType.split(",")).stream().map(s ->s.trim()).collect(Collectors.toList());
未完待續。。。