Employee 表包含所有員工資訊，每個員工有其對應的 Id, salary 和 department Id 。

±—±------±-------±-------------+
| Id | Name | Salary | DepartmentId |
±—±------±-------±-------------+
| 1 | Joe | 70000 | 1 |
| 2 | Henry | 80000 | 2 |
| 3 | Sam | 60000 | 2 |
| 4 | Max | 90000 | 1 |
| 5 | Janet | 69000 | 1 |
| 6 | Randy | 85000 | 1 |
±—±------±-------±-------------+
Department 表包含公司所有部門的資訊。

±—±---------+
| Id | Name |
±—±---------+
| 1 | IT |
| 2 | Sales |
±—±---------+
編寫一個 SQL 查詢，找出每個部門工資前三高的員工。例如，根據上述給定的表格，查詢結果應返回：

±-----------±---------±-------+
| Department | Employee | Salary |
±-----------±---------±-------+
| IT | Max | 90000 |
| IT | Randy | 85000 |
| IT | Joe | 70000 |
| Sales | Henry | 80000 |
| Sales | Sam | 60000 |
±-----------±---------±-------+

Write your MySQL query statement below

SELECT
d. NAME AS Department,
e. NAME AS Employee,
e.salary AS Salary
FROM
employee AS e
INNER JOIN department AS d ON e.DepartmentId = d.id
WHERE
(
SELECT
count(DISTINCT salary)
FROM
employee
WHERE
salary > e.salary
AND departmentid = e.DepartmentId
) < 3
ORDER BY
e.departmentid,
Salary DESC