《演算法基礎》所有演算法的Python實現
阿新 • • 發佈:2019-01-06
寫這篇文章並不是面向讀者的,主要就是當記筆記。
我的程式設計基礎太爛,我之前想我以後要搞工程,也不搞ACM,所以一直沒有重視演算法。但是現在想來,之前的想法就實在可笑了。演算法基礎不行,不論是搞工程還是搞學術,都太容易觸碰到自己的天花板。一句話:目光短淺!
現在打算每天晚上花1~2個小時用在演算法上。看演算法書或在網上刷題。
由於個人能力尚且太淺,如果真的有人看我下面的程式碼的話,還請多多指教!
為了比較效能,我寫了個用於函式計時的裝飾器:
import time
from functools import wraps
def ftimer(func):
@wraps(func)
def function_timer(*args,**kwargs):
t0=time.time()
result=func(*args,**kwargs)
t1=time.time()
print 'the running time of function "%s" is %.12f seconds' %(func.__name__,t1-t0)
return result
return function_timer
於是每次寫程式碼前要先
from decorators import ftimer
P12 LINEAR-SEARCH(A,n,x)
@ftimer
def linear_search(A,n,x):
ans='NOT_FOUND'
for i in range(n):
if A[i]==x:
ans=i+1
return ans
nums=[0,5,2,3,1,4,6]
n=len(nums)
x=int(raw_input('input a num to search:'))
ans=linear_search(nums,n,x)
print 'the anwser is',ans
P13 BETTER-LINEAR-SEARCH(A,n,x)
@ftimer
def linear_search(A,n,x):
ans='NOT_FOUND'
for i in range(n):
if A[i]==x:
ans=i+1
break
return ans
nums=[0,5,2,3,1,4,6]
n=len(nums)
x=int(raw_input('input a num to search:'))
ans=linear_search(nums,n,x)
print 'the anwser is',ans
P14 SENTINEL-LINEAR-SEARCH(A,n,x)
@ftimer
def linear_search(A,n,x):
last=A[n-1]
A[n-1]=x
i=0
while A[i]!=x:
i+=1
A[n-1]=last
if i<n-1 or A[n-1]==x:
return i+1
return 'NOT_FOUND'
nums=[0,5,2,3,1,4,6]
n=len(nums)
x=int(raw_input('input a num to search:'))
ans=linear_search(nums,n,x)
print 'the anwser is',ans
今天到此為止。打卡,嘀~
2017/9/28
插入排序
def insert_sort(lists):
# 插入排序
count = len(lists)
for i in range(1, count):
key = lists[i]
j = i - 1
while j >= 0:
if lists[j] > key:
lists[j + 1] = lists[j]
lists[j] = key
j -= 1
return lists
希爾排序
這個還需要好好研究一下
def shell_sort(lists):
# 希爾排序
count = len(lists)
step = 2
group = count / step
while group > 0:
for i in range(0, group):
j = i + group
while j < count:
k = j - group
key = lists[j]
while k >= 0:
if lists[k] > key:
lists[k + group] = lists[k]
lists[k] = key
k -= group
j += group
group /= step
return lists
氣泡排序
def bubble_sort(lists):
# 氣泡排序
count = len(lists)
for i in range(0, count):
for j in range(i + 1, count):
if lists[i] > lists[j]:
lists[i], lists[j] = lists[j], lists[i]
return lists
快速排序
這個還需要再看看
def quick_sort(lists, left, right):
# 快速排序
if left >= right:
return lists
key = lists[left]
low = left
high = right
while left < right:
while left < right and lists[right] >= key:
right -= 1
lists[left] = lists[right]
while left < right and lists[left] <= key:
left += 1
lists[right] = lists[left]
lists[right] = key
quick_sort(lists, low, left - 1)
quick_sort(lists, left + 1, high)
return lists
選擇排序
def select_sort(lists):
# 選擇排序
count = len(lists)
for i in range(0, count):
min = i
for j in range(i + 1, count):
if lists[min] > lists[j]:
min = j
lists[min], lists[i] = lists[i], lists[min]
return lists
歸併排序
def merge(left, right):
i, j = 0, 0
result = []
while i < len(left) and j < len(right):
if left[i] <= right[j]:
result.append(left[i])
i += 1
else:
result.append(right[j])
j += 1
result += left[i:]
result += right[j:]
return result
def merge_sort(lists):
# 歸併排序
if len(lists) <= 1:
return lists
num = len(lists) / 2
left = merge_sort(lists[:num])
right = merge_sort(lists[num:])
return merge(left, right)