CTF-web Xman-2018 第五天 WEB習題2
檢視原始碼
http://120.24.86.145:8002/web2/
沒什麼可說的 直接檢視原始碼就可以
帶有轉義的編碼
http://120.24.86.145:8002/web3/
進入之後看到一串奇怪的東西
KEY{J2sa42ahJK-HS11III} //這是html js的轉義的意思 直接alert(s)
百分號編碼
http://120.24.86.145:8002/web4/index.php
進去之後看到原始碼,原始碼裡都是這種經過編碼的百分號資料
escape採用ISO Latin字符集對指定的字串進行編碼。所有的空格符、標點符號、特殊字元以及其他非ASCII字元都將被轉化成%xx格式的字元編碼(xx等於該字元在字符集表裡面的編碼的16進位制數字)。所以也不用多說,瞭解有這個知識點就可以,所以下面就直接解碼了
<script> var p1 = '%66%75%6e%63%74%69%6f%6e%20%63%68%65%63%6b%53%75%62%6d%69%74%28%29%7b%76%61%72%20%61%3d%64%6f%63%75%6d%65%6e%74%2e%67%65%74%45%6c%65%6d%65%6e%74%42%79%49%64%28%22%70%61%73%73%77%6f%72%64%22%29%3b%69%66%28%22%75%6e%64%65%66%69%6e%65%64%22%21%3d%74%79%70%65%6f%66%20%61%29%7b%69%66%28%22%36%37%64%37%30%39%62%32%62'; var p2 = '%61%61%36%34%38%63%66%36%65%38%37%61%37%31%31%34%66%31%22%3d%3d%61%2e%76%61%6c%75%65%29%72%65%74%75%72%6e%21%30%3b%61%6c%65%72%74%28%22%45%72%72%6f%72%22%29%3b%61%2e%66%6f%63%75%73%28%29%3b%72%65%74%75%72%6e%21%31%7d%7d%64%6f%63%75%6d%65%6e%74%2e%67%65%74%45%6c%65%6d%65%6e%74%42%79%49%64%28%22%6c%65%76%65%6c%51%75%65%73%74%22%29%2e%6f%6e%73%75%62%6d%69%74%3d%63%68%65%63%6b%53%75%62%6d%69%74%3b'; eval(unescape(p1) + unescape('%35%34%61%61%32' + p2)); </script>
一看就是百分號編碼,拼接一下然後解碼一下
function checkSubmit()
{
var a=document.getElementById("password");
if("undefined"!=typeof a)
{
if("67d709b2b54aa2aa648cf6e87a7114f1"==a.value)
return!0;
alert("Error");
a.focus();
return!1
}
}
document.getElementById("levelQuest").onsubmit=checkSubmit;
在輸入框中輸入67d709b2b54aa2aa648cf6e87a7114f1得到flag
JSFUCK解碼
http://120.24.86.145:8002/web5
線上的顯示不出來,還是得用谷歌的控制檯
這個東西應該有點印象,形式如下:
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有一個線上的加密網站,http://www.jsfuck.com/
這是一段js程式碼,如果想要看看效果,把它放到你的控制檯裡面執行就可以了
Bp抓包 base64
http://120.24.86.145:8002/web6
進去是個網頁提醒你快點,原始碼無資訊,抓包發現響應頭有flag欄位,base64編碼的
解碼獲得flag,最好使用python或者notepad++,線上有時候抽風
入門坑爹題
http://120.24.86.145:8007/web2/index.php
看起來特別難的注入,過濾很多字元
實際上是一個DS_STORE原始碼洩露,下載指令碼ds_store_exp
py -2 ./ds_store_exp.py http://120.24.86.145:8007/web2/.DS_Store
下載到flag原始碼檔案。
sha對比繞過
http://120.24.86.145:8002/web7
網頁原始碼如下
<?php
highlight_file('flag.php');
$_GET['id'] = urldecode($_GET['id']);
$flag = 'flag{xxxxxxxxxxxxxxxxxx}';
if (isset($_GET['uname']) and isset($_POST['passwd'])) {
if ($_GET['uname'] == $_POST['passwd']) //兩者不能相同
print 'passwd can not be uname.';
else if (sha1($_GET['uname']) === sha1($_POST['passwd'])&($_GET['id']=='margin')) //sha1要相同 並且id引數值為margin
die('Flag: '.$flag);
else
print 'sorry!';
}
?>
要求uname和passwd經過sha1加密相等,這個不是碰撞,上網可以看到全世界就一例檔案碰撞的。
我們傳入不符合要求的陣列,使得均返回false造成相等,傳入id=margin