Java 8 – Convert List to Map(將 List 轉換為 Map)
阿新 • • 發佈:2019-01-07
幾個Java 8的例子展示怎樣將一個 物件的集合(List)放入一個Map中,並且展示怎樣處理多個重複keys的問題。
Hosting.javapackage com.mkyong.java8
public class Hosting {
private int Id;
private String name;
private long websites;
public Hosting(int id, String name, long websites) {
Id = id;
this.name = name;
this.websites = websites;
}
//getters, setters and toString()
}
1. List to Map – Collectors.toMap()
建立一個 Hosting
物件集合, 並且用 Collectors.toMap
去將它轉換放入一個
Map.
package com.mkyong.java8
import java.util.ArrayList;
import java.util.List;
import java.util.Map;
import java. util.stream.Collectors;
public class TestListMap {
public static void main(String[] args) {
List<Hosting> list = new ArrayList<>();
list.add(new Hosting(1, "liquidweb.com", 80000));
list.add(new Hosting(2, "linode.com", 90000));
list.add(new Hosting(3, "digitalocean.com" , 120000));
list.add(new Hosting(4, "aws.amazon.com", 200000));
list.add(new Hosting(5, "mkyong.com", 1));
// key = id, value - websites
Map<Integer, String> result1 = list.stream().collect(
Collectors.toMap(Hosting::getId, Hosting::getName));
System.out.println("Result 1 : " + result1);
// key = name, value - websites
Map<String, Long> result2 = list.stream().collect(
Collectors.toMap(Hosting::getName, Hosting::getWebsites));
System.out.println("Result 2 : " + result2);
// Same with result1, just different syntax
// key = id, value = name
Map<Integer, String> result3 = list.stream().collect(
Collectors.toMap(x -> x.getId(), x -> x.getName()));
System.out.println("Result 3 : " + result3);
}
}
Output
Result 1 : {1=liquidweb.com, 2=linode.com, 3=digitalocean.com, 4=aws.amazon.com, 5=mkyong.com}
Result 2 : {liquidweb.com=80000, mkyong.com=1, digitalocean.com=120000, aws.amazon.com=200000, linode.com=90000}
Result 3 : {1=liquidweb.com, 2=linode.com, 3=digitalocean.com, 4=aws.amazon.com, 5=mkyong.com}
2. List to Map – Duplicated Key! (List轉Map 重複key問題)
2.1 Run below code, and duplicated key errors will be thrown!
TestDuplicatedKey.javapackage com.mkyong.java8;
import java.util.ArrayList;
import java.util.List;
import java.util.Map;
import java.util.stream.Collectors;
public class TestDuplicatedKey {
public static void main(String[] args) {
List<Hosting> list = new ArrayList<>();
list.add(new Hosting(1, "liquidweb.com", 80000));
list.add(new Hosting(2, "linode.com", 90000));
list.add(new Hosting(3, "digitalocean.com", 120000));
list.add(new Hosting(4, "aws.amazon.com", 200000));
list.add(new Hosting(5, "mkyong.com", 1));
list.add(new Hosting(6, "linode.com", 100000)); // new line
// key = name, value - websites , but the key 'linode' is duplicated!?
Map<String, Long> result1 = list.stream().collect(
Collectors.toMap(Hosting::getName, Hosting::getWebsites));
System.out.println("Result 1 : " + result1);
}
}
輸出:下面這個錯誤有的誤導,它應該顯示 “linode” 代替key的值。
Exception in thread "main" java.lang.IllegalStateException: Duplicate key 90000
at java.util.stream.Collectors.lambda$throwingMerger$0(Collectors.java:133)
at java.util.HashMap.merge(HashMap.java:1245)
//...
2.2 為了解決上面重複key的問題,通過增加第三個引數解決:
Map<String, Long> result1 = list.stream().collect(
Collectors.toMap(Hosting::getName, Hosting::getWebsites,
(oldValue, newValue) -> oldValue
)
);
Output
Result 1 : {..., aws.amazon.com=200000, linode.com=90000}
Note(oldValue, newValue) -> oldValue
==> 如果key是重複的,你選擇oldKey or newKey?
3.3 Try newValue
Map<String, Long> result1 = list.stream().collect(
Collectors.toMap(Hosting::getName, Hosting::getWebsites,
(oldValue, newValue) -> newvalue
)
);
Output
Result 1 : {..., aws.amazon.com=200000, linode.com=100000}
3. List to Map – Sort & Collect
TestSortCollect.javapackage com.mkyong.java8;
import java.util.*;
import java.util.stream.Collectors;
public class TestSortCollect {
public static void main(String[] args) {
List<Hosting> list = new ArrayList<>();
list.add(new Hosting(1, "liquidweb.com", 80000));
list.add(new Hosting(2, "linode.com", 90000));
list.add(new Hosting(3, "digitalocean.com", 120000));
list.add(new Hosting(4, "aws.amazon.com", 200000));
list.add(new Hosting(5, "mkyong.com", 1));
list.add(new Hosting(6, "linode.com", 100000));
//example 1
Map result1 = list.stream()
.sorted(Comparator.comparingLong(Hosting::getWebsites).reversed())
.collect(
Collectors.toMap(
Hosting::getName, Hosting::getWebsites, // key = name, value = websites
(oldValue, newValue) -> oldValue, // if same key, take the old key
LinkedHashMap::new // returns a LinkedHashMap, keep order
));
System.out.println("Result 1 : " + result1);
}
}
Output
Result 1 : {aws.amazon.com=200000, digitalocean.com=120000, linode.com=100000, liquidweb.com=80000, mkyong.com=1}
P.S 在上面的例子中, stream 在collect 之前已經被排序, 所以 “linode.com=100000”變為 ‘oldValue’.