獲取硬碟分割槽表的格式--是gpt還是mbr
阿新 • • 發佈:2019-01-07
MSDN:DeviceIoControl
與硬體驅動互動時,DeviceIoControl 是常用的windows API。 它把控制碼發給制定的硬體驅動,然後獲取裝置資訊或者對裝置進行其他操作。 下面是一個小demo
#include<iostream>
#include<windows.h>
using namespace std;
int main()
{
TCHAR szDiskPos[128] = L"\\\\.\\PhysicalDrive0"; //ff
HANDLE hDevice = INVALID_HANDLE_VALUE;
int nDiskBufferSize = sizeof(PARTITION_INFORMATION_EX);
PARTITION_INFORMATION_EX * lpDiskPartinfo_ex = (PARTITION_INFORMATION_EX *)malloc(nDiskBufferSize);
DWORD nDiskBytesRead = 0;
memset(lpDiskPartinfo_ex, 0, sizeof(lpDiskPartinfo_ex));
hDevice = CreateFile(szDiskPos, GENERIC_READ, FILE_SHARE_READ | FILE_SHARE_WRITE, NULL , OPEN_EXISTING, 0, NULL);
BOOL Ret = FALSE;
Ret = DeviceIoControl(hDevice, IOCTL_DISK_GET_PARTITION_INFO_EX, NULL, 0, lpDiskPartinfo_ex, nDiskBufferSize, &nDiskBytesRead, NULL);
if(!Ret)
{
int e = GetLastError();
cout<<strerror(e)<<endl;
}
if(lpDiskPartinfo_ex->PartitionStyle == PARTITION_STYLE_MBR )
{
cout <<"MBR"<<endl;
}else if(lpDiskPartinfo_ex->PartitionStyle == PARTITION_STYLE_GPT )
{
cout<<"GPT"<<endl;
}else if(lpDiskPartinfo_ex->PartitionStyle == PARTITION_STYLE_RAW )
{
cout<<"RAW"<<endl;
}
free(lpDiskPartinfo_ex);
lpDiskPartinfo_ex = NULL;
CloseHandle(hDevice);
cin.get();
return 0;
}
這寫這個小demo的時候,犯了一個錯誤,使用了一個不再支援的控制碼IOCTL_DISK_GET_DRIVE_LAYOUT
而在MSDN上也已經警告過了
Note IOCTL_DISK_GET_DRIVE_LAYOUT has been superseded by IOCTL_DISK_GET_DRIVE_LAYOUT_EX, which retrieves layout information for AT and EFI (Extensible Firmware Interface) partitions.
而我卻把這句話理解反了,使用IOCTL_DISK_GET_DRIVE_LAYOUT得不到想要的資料,雖然編譯是成功的,執行也沒有報錯,這導致後面浪費了好多時間。