SDUT 2142 資料結構實驗之圖論二:基於鄰接表的廣度優先搜尋遍歷
阿新 • • 發佈:2019-01-08
點選開啟題目連結
#include <bits/stdc++.h> using namespace std; struct node { int data; node *next; }; node *head[1010], *p; void BFS(int s); bool vis[1010]; int n, m, s; int main() { int k; cin >> k; for(int i = 0; i < 1010; i++) { head[i] = new node; } while(k --) { memset(vis, 0, sizeof(vis)); cin >> n >> m >> s; for(int i = 0; i < n; i++) { head[i] -> next = NULL; } for(int i = 0; i < m; i++) { int u, v; cin >> u >> v; p = new node; p -> data = v; p -> next = head[u] -> next; head[u] -> next = p; p = new node; p -> data = u; p -> next = head[v] -> next; head[v] -> next = p; } BFS(s); cout << endl; } return 0; } void BFS(int s) { for(int i = 0; i < m; i++)//(同一個結點的同層鄰接點,節點編號小的優先遍歷)排序,將節點小的放在之前; { for(node *p = head[i] -> next; p; p = p -> next) { for(node *q = p -> next; q; q = q -> next) { if(p -> data > q -> data) { int tmp = p -> data; p -> data = q -> data; q -> data = tmp; } } } } int q; queue<int >Q; Q.push(s); vis[s] = 1; while(!Q.empty()) { cout << (q = Q.front()) << ' '; Q.pop(); for(p = head[q] -> next; p; p = p -> next) { if(!vis[p -> data]) { vis[p -> data] = 1; Q.push(p -> data); } } } }