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Leetcode之Count and Say

題目:

The count-and-say sequence is the sequence of integers with the first five terms as following:

1.     1
2.     11
3.     21
4.     1211
5.     111221

1 is read off as "one 1" or 11.
11 is read off as "two 1s" or 21.
21 is read off as "one 2, then one 1"

 or 1211.

Given an integer n where 1 ≤ n ≤ 30, generate the nth term of the count-and-say sequence.

Note: Each term of the sequence of integers will be represented as a string.

 

Example 1:

Input: 1
Output: "1"

Example 2:

Input: 4
Output: "1211"

程式碼:

class Solution {
public:
    string countAndSay(int n) {
        if (n < 1 || n>30) return "";
	if (n == 1)return "1";
	string last = countAndSay(n - 1);
	char c='.';
	string res = "";int count = 0;
	for (int i = 0; i < last.length(); i++) {
		
		if (c != last[i]) {
			if (count != 0) {
				string s1 = to_string(count);
				s1.push_back(c);
				res += s1 ;
		   }
			c = last[i];
			count = 1;
		}
		else count++;
	}

	
	string s1 = to_string(count);
	s1.push_back(c);
	res += s1 ;
	return res;
    }
};

注:

1、使用遞迴的思路求解

2、學會不同型別之間的轉換:int 轉為 string---to_string(),char轉為string---s.push_back()