Leetcode之Count and Say
阿新 • • 發佈:2019-01-08
題目:
The count-and-say sequence is the sequence of integers with the first five terms as following:
1. 1 2. 11 3. 21 4. 1211 5. 111221
1
is read off as "one 1"
or 11
.11
is read off as "two 1s"
or 21
.21
is read off as "one 2
, then one 1"
1211
.
Given an integer n where 1 ≤ n ≤ 30, generate the nth term of the count-and-say sequence.
Note: Each term of the sequence of integers will be represented as a string.
Example 1:
Input: 1 Output: "1"
Example 2:
Input: 4 Output: "1211"
程式碼:
class Solution { public: string countAndSay(int n) { if (n < 1 || n>30) return ""; if (n == 1)return "1"; string last = countAndSay(n - 1); char c='.'; string res = "";int count = 0; for (int i = 0; i < last.length(); i++) { if (c != last[i]) { if (count != 0) { string s1 = to_string(count); s1.push_back(c); res += s1 ; } c = last[i]; count = 1; } else count++; } string s1 = to_string(count); s1.push_back(c); res += s1 ; return res; } };
注:
1、使用遞迴的思路求解
2、學會不同型別之間的轉換:int 轉為 string---to_string(),char轉為string---s.push_back()