/* 一個查詢包含的sql 語句 條件：任意一個id，例：id=1 需求：得到name值包含條件id的name的id 例：既包含a又包含b的id 思路：一開始想著用 join 或者 exists 來解決,費勁不少,解決了 但是問題是id不固定，name多少不固定.......... 如果是id=n又有a,b又有c,d,e... 要寫5個6個n個join還是exists....... */ if object_id('[tb]') is not null drop table [tb] create table [tb]([id] int,[name] varchar(1)) insert [tb] select 1,'a' union all select 1,'b' union all select 2,'a' union all select 2,'c' union all select 3,'a' union all select 3,'b' union all select 3,'c' union all select 4,'a' union all select 4,'b' union all select 4,'d' union all select 5,'a' union all select 5,'b' union all select 5,'c' union all select 5,'d' go select [id] from [tb] where [name] in (select [name] from [tb] where [id]=1) group by [id] having count(distinct [name])>=(select count(1) from [tb] where [id]=1)