LeetCode7 給定一個 32 位有符號整數,將整數中的數字進行反轉。
阿新 • • 發佈:2019-01-10
class Solution {
public:
int reverse(int x) {
long long x1 = abs(x);
long long y=0, n=0;
std::vector<int> i;
while(x1/(long long)(pow(double(10),int(n))))
{
i.push_back(x1%(long long)(pow(double(10),int(n+1)))/(long long)(pow(double(10),int(n))));
++n;
}
for (int j = 0; j < i.size(); ++j)
{
auto d = (long long)(pow(double(10),int(i.size()-j-1)));
auto b = (long long)(i[j]);
y += b*d;
}
if(x < 0)
{
y = -y;
}
if(y < (-pow(double(2),31)) || y > (pow(double (2),31)-1))
return 0;
return y;
}
};