Jim has a balance and N weights. (1≤N≤20)(1≤N≤20) 
The balance can only tell whether things on different side are the same weight. 
Weights can be put on left side or right side arbitrarily. 
Please tell whether the balance can measure an object of weight M.

Input

The first line is a integer T(1≤T≤5)T(1≤T≤5), means T test cases. 
For each test case : 
The first line is NN, means the number of weights. 
The second line are NN number, i'th number wi(1≤wi≤100)wi(1≤wi≤100) means the i'th weight's weight is wiwi. 
The third line is a number MM. MM is the weight of the object being measured.

Output

You should output the "YES"or"NO".

Sample Input

1
2
1 4
3
2
4
5

Sample Output

NO
YES
YES


        
 

Hint

For the Case 1:Put the 4 weight alone
For the Case 2:Put the 4 weight and 1 weight on both side
        

題解：01揹包型別的題，正著掃一遍求和，倒著掃一遍求差就行了;

#include <iostream>
#include <cstring>
using namespace std;
int t, n, m;
int a[25], dp[2500];

void solve()
{
    memset(dp,0,sizeof(dp));
    dp[0]=1;
    for(int i=0; i<n; i++)
        for(int j=2100; j>=a[i]; j--)
            dp[j]|=dp[j-a[i]];//正著掃一遍;
    for(int i=0; i<n; i++)
        for(int j=1; j<=2100; j++)
            dp[j]|=dp[j+a[i]];;//倒著掃一遍;
}
int main()
{
    cin>>t;
    while(t--)
    {
        cin>>n;
        for(int i=0; i<n; i++)
            cin>>a[i];
        solve();
        cin>>m;
        while(m--)
        {
            int x;
            cin>>x;
            if(dp[x]) cout<<"YES"<<endl;
            else cout<<"NO"<<endl;
        }
    }
    return 0;
}