給出一個不多於五位的正整數，要求輸出它的位數，每一位數字及逆序
阿新 • • 發佈：2019-01-10
#include<stdio.h> #include<math.h> int main() { int a,b,c,d,e,f; int count=0; printf("input a:\n"); scanf("%d",&a); if(a>9999) { count=5; } else if(a>999) { count=4; } else if(a>99) { count=3; } else if(a>9) { count=2; } else { count=1; } printf("count=%d\n",count); printf("它的每一位數字為:"); b=a/10000; c=(int)(a-b*10000)/1000; d=(int)(a-b*10000-c*1000)/100; e=(int)(a-b*10000-c*1000-d*100)/10; f=(int)(a-b*10000-c*1000-d*100-e*10); switch(count) { case 5:printf("%d%d%d%d%d",b,c,d,e,f); printf("\n反序數字為:\n"); printf("%d%d%d%d%d",f,e,d,c,b); break; case 4:printf("%d%d%d%d",c,d,e,f); printf("\n反序數字為:\n"); printf("%d%d%d%d",f,e,d,c); break; case 3:printf("%d%d%d",d,e,f); printf("\n反序數字為:\n"); printf("%d%d%d",f,e,d); break; case 2:printf("%d%d",e,f); printf("\n反序數字為:\n"); printf("%d%d",f,e); break; case 1:printf("%d",f); printf("\n反序數字為:\n"); printf("%d",f); break; } printf("\n"); return 0; }