A + B Again

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 15772    Accepted Submission(s): 6847


Problem Description There must be many A + B problems in our HDOJ , now a new one is coming.
Give you two hexadecimal integers , your task is to calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it !
Input The input contains several test cases, please process to the end of the file.
Each case consists of two hexadecimal integers A and B in a line seperated by a blank.
The length of A and B is less than 15.
Output For each test case,print the sum of A and B in hexadecimal in one line.

Sample Input +A -A +1A 12 1A -9 -1A -12 1A -AA
Sample Output 0 2C 11 -2C -90
Author linle
Source

1.%I64X 輸入

2.%I64X 不能輸出負數

3.%I64O 也不能輸出負數

4.如果x 為小寫 輸出的16進製為小寫，為大寫，輸出大寫

#include <cstdio>  
#include <cstdlib>  
#include <cmath>  
#include <cstring>  
#include <ctime>  
#include <algorithm>  
#include <iostream>
#include <sstream>
#include <string>
#define oo 0x13131313   
using namespace std;
int main()
{
	long long A;long long B;
	while(scanf("%I64O%I64O",&A,&B)!=EOF)
	{
		long long C=A+B;
	//	if(C<0) 
	//	printf("-%I64X\n",-C);
		 printf("%I64o\n",C);
	}
	return 0;
}