Android List(集合)中的物件以某一個欄位排序
阿新 • • 發佈:2019-01-10
在Android開發中,有時我們需要對一個物件的集合按照某一個欄位進行排序,
- Bean
public class Student {
private int studentId;
private String studentName;
private int age;
public Student(int studentId , String studentName, int age){
this.studentId=studentId;
this.studentName=studentName;
this .age=age;
}
public int getStudentId() {
return studentId;
}
public void setStudentId(int studentId) {
this.studentId = studentId;
}
public String getStudentName() {
return studentName;
}
public void setStudentName(String studentName) {
this .studentName = studentName;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
}
實現排序
實現排序比較類 Comparator ,裡面實現排序規則。
public class test {
/**
* @param args
*/
public static void main(String[] args) {
Student stu1 = new Student (1,"zhangsan",28);
Student stu2 = new Student (2,"zhagnsan",19);
Student stu3 = new Student (3,"wangwu",19);
Student stu4 = new Student (4,"wangwu",19);
Student stu5 = new Student (5,"zhaoliu",18);
ArrayList<Student> list = new ArrayList<Student>();
list.add(stu1);
list.add(stu2);
list.add(stu3);
list.add(stu4);
list.add(stu5);
//排序規則,這裡是以年齡先排序,如果年齡相同
Comparator<Student> comparator = new Comparator<Student>() {
public int compare(Student s1, Student s2) {
// 先排年齡
if (s1.getAge() != s2.getAge()) {
return s1.getAge() - s2.getAge();
} else if (!s1.getStudentName().equals(s2.getStudentName())) {
// 年齡相同則按姓名排序
return s1.getStudentName().compareTo(s2.getStudentName());
} else {
// 姓名也相同則按學號排序
return s1.getStudentId() - s2.getStudentId();
}
}
};
//這裡就會自動根據規則進行排序
Collections.sort(list,comparator);
for(int i=0;i<list.size();i++){
Student stu=list.get(i);
System.out.println("年齡:"+stu.getAge()+" 姓名:"+stu.getStudentName()+" 學號:"+stu.getStudentId());
}
}
}
排序結果
結果:
年齡:18 姓名:zhaoliu 學號:5
年齡:19 姓名:wangwu 學號:3
年齡:19 姓名:wangwu 學號:4
年齡:19 姓名:zhagnsan 學號:2
年齡:28 姓名:zhangsan 學號:1
也可以想下面這樣寫:
Collections.sort(list, new Comparator<GoodsBean>() {
@Override
public int compare(GoodsBean bean1, GoodsBean bean2) {
if (Integer.valueOf(bean1.getScore()).compareTo(Integer.valueOf(bean2.getScore())) == 0) {
return Integer.valueOf(bean1.getRecommend_num()).compareTo(Integer.valueOf(bean2.getRecommend_num()));
} else {
return Integer.valueOf(bean1.getScore()).compareTo(Integer.valueOf(bean2.getScore()));
}
}
});
這樣就可以對一個集合中的資料各種排序了。