YAML的Java實現——JYAML基本原理與示例(2)匯入YAML格式檔案
阿新 • • 發佈:2019-01-11
1. 定義好的YAML檔案testYaml.yaml
--- &0 !com.sinosuperman.yaml.Person age: 24 children: &2 !com.sinosuperman.yaml.Person[] - !com.sinosuperman.yaml.Person age: 3 name: boy - !com.sinosuperman.yaml.Person age: 1 name: girl name: Michael Corleone spouse: !com.sinosuperman.yaml.Person age: 24 children: *2 name: Floveria Edie spouse: *0
或無型別資訊的testYaml2.yaml
--- &0
age: 24
children: &2
-
age: 3
name: boy
-
age: 1
name: girl
name: Michael Corleone
spouse:
age: 24
children: *2
name: Floveria Edie
spouse: *0
2. 匯入YAML檔案
try { Person corleone = (Person) Yaml.loadType(dumpFile, Person.class); Person corleone2 = (Person) Yaml.loadType(dumpFile2, Person.class); output(corleone); System.out.println(); output(corleone2); } catch (FileNotFoundException e) { e.printStackTrace(); } ... private static void output(Person person) { System.out.println("Name: " + person.getName()); System.out.println("Age: " + person.getAge()); System.out.println("Spouse: " + person.getSpouse().getName()); System.out.println("Children: " + person.getChildren()[0].getName() + ", " + person.getChildren()[1].getName()); }