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連結串列奇偶分離,並且連結串列反轉

題目:

將連結串列中的所有元素為奇數的節點移到元素為偶數節點的前面,並使奇數之間順序反轉,偶數之間順序反轉。

示例:

交換前連結串列的順序           交換後連結串列的順序

4→5→7→1→6   ==>  1→7→5→6→4

1                ==>  1                   (連結串列僅含一個元素)

2→1            ==>  1→2 

                   ==>                        (連結串列為空)

思路:定義奇數偶數分別的連結串列,

原連結串列  2—>3—>4—>5—>6:

結果:5—>3—>6—>4—>2

奇數連結串列:3—>5

偶數連結串列:2—>4—>6

偶數+奇數:2—>4—>6—>3—>5

反轉連結串列5—>3—>6—>4—>2

package exam;
/*
 * 連結串列保持順序奇數在前偶數在後,並且反轉連結串列
 */

public class Demo {
	public static void main(String[] args) {
		Node n1 = new Node(2);
		Node n2 = new Node(3);
		Node n3 = new Node(4);
		Node n4 = new Node(5);
		Node n5 = new Node(6);

		n1.next = n2;
		n2.next = n3;
		n3.next = n4;
		n4.next = n5;
		Node n = getOddEvenNode(n1);
		System.out.println(n);
	}

	// 奇數偶數歸類
	public static Node getOddEvenNode(Node node) {
		if (node == null || node.next == null)
			return node;
		Node oddHead = new Node(0);
		Node odd = new Node(0);
		oddHead.next = odd;
		Node evenHead = new Node(0);
		Node even = new Node(0);
		evenHead.next = even;
		int k = 0;
		while (node != null) {
			if (node.val % 2 == 0) {
				even.next = node;
				even = even.next;
			} else {
				odd.next = node;
				odd = odd.next;
			}
			k++;
			node = node.next;
		}

		even.next = oddHead.next.next;
		node = evenHead.next.next;

		return reverse(node, k);
	}

	// 反轉連結串列 ,統計個數,定義頭結點head,定義初始尾節點是node的第一個節點,後面的每個節點都插入到head和next中間,next不斷的變化
	public static Node reverse(Node node, int k) {
		Node head = new Node(0);
		// 中間節點,儲存每次node下一個值,
		Node interNode = null;
		interNode = node.next;
		node.next = null;
		Node next = node;
		head.next = node;
		node = interNode;
		int inter = 1;

		while (node != null && inter != k) {
			interNode = node.next;
			node.next = null;
			head.next = node;
			node.next = next;
			next = node;
			node = interNode;
			inter++;
		}
		return head.next;
	}
}