LeetCode 23 Merge k Sorted Lists 高空間消耗解法與堆的解法,還需要學習堆的做法
Merge k Sorted Lists
Merge k sorted
linked lists and return it as one sorted list. Analyze and describe its complexity.
解法思路:我的想法是,首先利用O(n^2)的遍歷,將所有值存到整型陣列當中,將陣列排序,輸出到一個新的連結串列當中,思路非常清晰,效率也還不錯。但是這樣的演算法有著較高的記憶體開銷,並且沒有利用連結串列的特性。因此,不提倡這種類似於作弊的演算法。雖然能夠解決K-lists類的問題,但是,對於記憶體有要求的情景下,該演算法就面臨較大的考驗。
程式碼如下:
public ListNode mergeKLists(ListNode[] lists) { if(lists.length==0){ return null; } int []num = new int[5000]; int index=0; for (int i = 0; i < lists.length; i++) { ListNode l = lists[i]; while(l!=null){ num[index]=l.val; l = l.next; index++; } } if(index==0){ return null; } Arrays.sort(num,0,index); ListNode temp1 = new ListNode(-1);// l1 l2 首尾相連 然後冒泡 ListNode t1 = temp1; int i =0; while(i!=index){ temp1.val = num[i++]; if(i!=index){ temp1.next = new ListNode(0); } temp1 = temp1.next; } return t1; }
堆的方法詳解見這個演算法:
http://blog.csdn.net/linhuanmars/article/details/19899259?utm_source=tuicool
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