select * from 表名 where to_days(時間欄位名) = to_days(now());
昨天

SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) - TO_DAYS( 時間欄位名) <= 1
近7天

SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(時間欄位名)
近30天

SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(時間欄位名)
本月

SELECT * FROM 表名 WHERE DATE_FORMAT( 時間欄位名, ‘%Y%m’ ) = DATE_FORMAT( CURDATE( ) , ‘%Y%m’ )
上一月

SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , ‘%Y%m’ ) , date_format( 時間欄位名, ‘%Y%m’ ) ) =1
查詢本季度資料

select * from ht_invoice_information where QUARTER(create_date)=QUARTER(now());
查詢上季度資料

select * from ht_invoice_information where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));
查詢本年資料

select * from ht_invoice_information where YEAR(create_date)=YEAR(NOW());
查詢上年資料

select * from ht_invoice_information where year(create_date)=year(date_sub(now(),interval 1 year));
查詢當前這周的資料

SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,’%Y-%m-%d’)) = YEARWEEK(now());
查詢上週的資料

SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,’%Y-%m-%d’)) = YEARWEEK(now())-1;
查詢上個月的資料

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select name,submittime from enterprise where date_format(submittime,’%Y-%m’)=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),’%Y-%m’)

select * from user where DATE_FORMAT(pudate,’%Y%m’) = DATE_FORMAT(CURDATE(),’%Y%m’) ;

select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,’%y-%m-%d’)) = WEEKOFYEAR(now())

select * from user where MONTH(FROM_UNIXTIME(pudate,’%y-%m-%d’)) = MONTH(now())

select * from user where YEAR(FROM_UNIXTIME(pudate,’%y-%m-%d’)) = YEAR(now()) and MONTH(FROM_UNIXTIME(pudate,’%y-%m-%d’)) = MONTH(now())

select * from user where pudate between 上月最後一天 and 下月第一天
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查詢當前月份的資料

select name,submittime from enterprise where date_format(submittime,’%Y-%m’)=date_format(now(),’%Y-%m’)
查詢距離當前現在6個月的資料

select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();

查詢某個月的資料(查詢17年10月份資料)

select * from exam where date_format(starttime,’%Y-%m’)=‘2017-10’

select * from exam where date_format(starttime,’%Y-%m’)=date_format(‘2017-10-05’,’%Y-%m’)