SQL練習總結
阿新 • • 發佈:2019-01-17
是否 客戶 ssi sam last 總結 manage 查詢 join
表和
【SQL語句練習】
1.
表1: Person
+-------------+---------+ | 列名 | 類型 | +-------------+---------+ | PersonId | int | | FirstName | varchar | | LastName | varchar | +-------------+---------+ PersonId 是上表主鍵
表2: Address
+-------------+---------+ | 列名 | 類型 | +-------------+---------+ | AddressId | int | | PersonId | int | | City | varchar | | State | varchar | +-------------+---------+ AddressId 是上表主鍵
編寫一個 SQL 查詢,滿足條件:無論 person 是否有地址信息,都需要基於上述兩表提供 person 的以下信息:
FirstName, LastName, City, State
select FirstName, LastName, City, State from Person left join Address on Person.PersonId = Address.PersonId
2.
Employee
表包含所有員工,他們的經理也屬於員工。每個員工都有一個 Id,此外還有一列對應員工的經理的 Id。
+----+-------+--------+-----------+ | Id | Name | Salary | ManagerId | +----+-------+--------+-----------+ | 1 | Joe | 70000 | 3 | | 2 | Henry | 80000 | 4 | | 3 | Sam | 60000 | NULL | | 4 | Max | 90000 | NULL | +----+-------+--------+-----------+
給定 Employee
表,編寫一個 SQL 查詢,該查詢可以獲取收入超過他們經理的員工的姓名。在上面的表格中,Joe 是唯一一個收入超過他的經理的員工。
+----------+ | Employee | +----------+ | Joe | +----------+
select e1.name as Employee from Employee e1 inner join Employee e2 on e1.ManagerId = e2.Id where e1.Salary > e2.Salary
3.
某網站包含兩個表,Customers
Orders
表。編寫一個 SQL 查詢,找出所有從不訂購任何東西的客戶。
Customers
表:
+----+-------+ | Id | Name | +----+-------+ | 1 | Joe | | 2 | Henry | | 3 | Sam | | 4 | Max | +----+-------+
Orders
表:
+----+------------+ | Id | CustomerId | +----+------------+ | 1 | 3 | | 2 | 1 | +----+------------+
例如給定上述表格,你的查詢應返回:
+-----------+ | Customers | +-----------+ | Henry | | Max | +-----------+
select Name as Customers from Customers where Id not in (select CustomerId from Orders)
SQL練習總結