org.springframework.web.HttpMediaTypeNotAcceptableException: Could not find acceptable representation

spring從3.1升級到4.1.3 json 處理失敗

報出以上錯誤。

折騰了半天 最終找到解決辦法 

spring 配置

    <!-- mvc:annotation-driven使用註解功能 -->  
    <mvc:annotation-driven>  
        <mvc:message-converters register-defaults="true">  
            <!--json處理-->  
            <bean  
                class="org.springframework.http.converter.json.MappingJackson2HttpMessageConverter">  
                <property name="supportedMediaTypes">  
                    <list>  
                        <value>application/json;charset=UTF-8</value>  
                        <value>text/html;charset=UTF-8</value>  
                    </list>  
                </property>  
            </bean>  
        </mvc:message-converters>  
    </mvc:annotation-driven>  
 

pom 使用

<!-- Jackson -->
		<dependency>
			<groupId>com.fasterxml.jackson.core</groupId>
			<artifactId>jackson-databind</artifactId>
			 <version>2.6.3</version>
		</dependency> 
		 <dependency>
		    <groupId>com.fasterxml.jackson.core</groupId>
		    <artifactId>jackson-core</artifactId>
				 <version>2.6.3</version>
		</dependency>
		<dependency>
		    <groupId>com.fasterxml.jackson.core</groupId>
		    <artifactId>jackson-annotations</artifactId>
		    	 <version>2.6.0</version>
		</dependency>
 

java 呼叫

	@RequestMapping(value = "login"  , method = RequestMethod.GET ) //, method = RequestMethod.GET
	@ResponseBody
	public 	 Map<String, Object> loginuser(@Valid INLoginUser inLoginUser) throws JsonProcessingException{ // @Uid String uid
		//int count = userService.modifyPassword(onlineUser.getUserId(), oldPwd, newPwd);
		Map<String, Object> personalLogin = userService.loginNew(inLoginUser.getUsername(), inLoginUser.getPassword());
		OnlineUser user = (OnlineUser) personalLogin.get("onlineUser");
		if (user != null) {
			Long token = user.getUserId()*31+12345 ;
			Map<String, Object> returnMap = new HashMap<String, Object>();
			returnMap.put("token", token);
			returnMap.put("user", user);
			return Ajax.getSuccessReturnMapWithData(returnMap);
		} else {
			String error = (String) personalLogin.get("error");
			return Ajax.buildErrorResult(error);
		}
	}
 

參考 :https://my.oschina.net/u/2273085/blog/476790