Given number n. Print number from 1 to n. But:

• when number is divided by 3, print "fizz".
• when number is divided by 5, print "buzz".
• when number is divided by both 3 and 5, print "fizz buzz".

Example

If n = 15, you should return:

[
  "1", "2", "fizz",
  "4", "buzz", "fizz",
  "7", "8", "fizz",
  "buzz", "11", "fizz",
  "13", "14", "fizz buzz"
]
 

解題思路：

1、非常簡單，不過要對vector類的成員函式有所瞭解，最後一種情況需要將int型資料push_back進入，可是push_back()函式只接受它本身的string型別，不能直接傳遞，這裡需要把int轉換為string，用to_string()函式即可。

class Solution {
public:
    /*
     * @param n: An integer
     * @return: A list of strings.
     */
    vector<string> fizzBuzz(int n) 
    {
        // write your code here
        vector<string> temp;
        
        for(int i=1;i<=n;i++)
        {
            if(i%3==0 && i%5==0)
            {
                temp.push_back("fizz buzz");
            }
            else if(i%3==0)
            {
                temp.push_back("fizz");
            }
            else if(i%5==0)
            {
                temp.push_back("buzz");
            }
            else
            {
                temp.push_back(to_string(i));
            }
        }
        
        return temp;
    }
};
 

JAVA程式碼：

public class Solution {
    /**
     * @param n: An integer
     * @return: A list of strings.
     */
    public List<String> fizzBuzz(int n) {
        // write your code here
        List<String> list = new ArrayList<>(n);
        
        for(int i=1 ; i<=n ; i++){
            if(i%3 == 0 && i%5 == 0){
                list.add("fizz buzz");
            }else if(i%3 == 0){
                list.add("fizz");
            }else if(i%5 == 0){
                list.add("buzz");
            }else{
                list.add(Integer.toString(i)); //也可用String.valueOf(i)
            }
        }
        
        return list;
    }
}