1. First the DispatcherServlet is invoked by the Servlet Container.

2. The DispatcherServlet finds a mapping which maps to the home method of your Controller and the home method returns a view name "HelloWorld"

3. Now the DispatcherServlet uses a View Resolver (your InternalResourceViewResolver) to find the View to render the model through, since the name is "HelloWorld", this maps to the /WEB-INF/view/HelloWorld.html view.

4. Now essentially a call is made to RequestDispatcher.forward("/WEB-INF/views/HelloWorld.html",....

5. The Servlet container at this point tries to find the servlet which can handle /WEB-INF/views/HellowWorld.html uri - if it had been a .jsp there is a JSPServlet registered which can handle rendering the jsp, however for *.html there is no servlet registered, so the call ends up with the "default servlet", which is registered with a servlet-mapping of / which probably your DispatcherServlet is.

6. Now the Dispatcher servlet does not find a controller to handle request for /WEB-INF/views/HelloWorld.html and hence the message that you are seeing

已經很清楚的告訴我們了即使你：

<bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver">

        <property name="prefix" value="/WEB-INF/views/"/>

        <property name="suffix" value=".html"/>

    </bean>

這樣配置了

但是你可愛的Web 容器並不知道，你到底要幹嘛？解析的是個What.所以你需要在web中註冊一下：

<servlet-mapping>

<servlet-name>jsp</servlet-name>

<url-pattern>*.html</url-pattern>

</servlet-mapping>

順道說一句JSP不是和html一樣的，只是個檔案字尾名而已，一句半句也說不清楚，感興趣的朋友可以翻翻相關資料。