給定一個簡單的四則運算的多項式，如果把多項式看作一個字串，試編寫程式，自左向右依次輸出每個子字串所對應的多項式的計算結果。例如給定多項式為：1+23*2+3*3，程式輸出結果為：1 3 24 47 50 56

key_list = [str(i) for i in range(1, 10)]

def func(str_in):
    if len(str_in) == 0:
        print 'Input Error 111!'
    result = 0
    result_f = 0
    pos = 0
    oper = 0
    num_f = 0
    num_list = []
    oper_list = []
    print str_in
    while pos < len(str_in):
        if pos == 0 and str_in[pos] in key_list:
            num = int(str_in[pos])
            num_list.append(num)
            #print num_list
            result = num_list[0]
            result_f = 0
            print result
        elif pos < len(str_in) and str_in[pos] in key_list:
            num = int(str_in[pos])
            if num_f == 0:
                num_f = num
                num_list.append(num_f)
            else:
                num_f = num_f*10 + num
                num_list[-1] = num_f
                #print num_list
                #print oper_list
            if oper_list[-1] == 1:
                result = result_f + num_list[-1]
            else:
                result = result_f + num_list[-2] * num_list[-1]
            print result
        elif pos < len(str_in) and str_in[pos] == '+':
            oper = 1
            num_f = 0
            result_f = result
            oper_list.append(oper)
        elif pos < len(str_in) and str_in[pos] == '*':
            oper = 2
            num_f = 0
            oper_list.append(oper)
        else:
            pass
        pos += 1


str_in = '1+23*2+3*3'
func(str_in)