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leetcode第47題(binary-tree-level-order-traversal)

題目:

Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). 

For example:
Given binary tree{3,9,20,#,#,15,7}, 

    3
   / \
  9  20
    /  \
   15   7

return its level order traversal as: 

[
  [3],
  [9,20],
  [15,7]
]

OJ's Binary Tree Serialization:

The serialization of a binary tree follows a level order traversal, where '#' signifies a path terminator where no node exists below. 

Here's an example: 

   1
  / \
 2   3
    /
   4
    \
     5
The above binary tree is serialized as"{1,2,3,#,#,4,#,#,5}". 

思路:

跟前面42題一樣,只是最後加的時候不加在頭部即可。

程式碼:

import 
java.util.ArrayList; import java.util.Collections; import java.util.LinkedList; import java.util.Queue; /** * Definition for binary tree * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { public
ArrayList<ArrayList<Integer>> levelOrder(TreeNode root) { ArrayList<ArrayList<Integer>> result = new ArrayList<ArrayList<Integer>>(); if(root==null){ return result; } Queue<TreeNode> que = new LinkedList<TreeNode>(); que.add(root); while(!que.isEmpty()){ int count = que.size(); ArrayList<Integer> list = new ArrayList<Integer>(); for(int i=0;i<count;i++){ TreeNode node = que.poll(); list.add(node.val); if(node.left!=null){ que.add(node.left); } if(node.right != null){ que.add(node.right); } } result.add(list); } return result; } }

Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). 

For example:
Given binary tree{3,9,20,#,#,15,7}, 

    3
   / \
  9  20
    /  \
   15   7

return its level order traversal as: 

[
  [3],
  [9,20],
  [15,7]
]

OJ's Binary Tree Serialization:

The serialization of a binary tree follows a level order traversal, where '#' signifies a path terminator where no node exists below. 

Here's an example: 

   1
  / \
 2   3
    /
   4
    \
     5
The above binary tree is serialized as"{1,2,3,#,#,4,#,#,5}".