對於前後端分離的情況下，ajax請求在過濾器和攔截器中，都不能直接返回頁面，那麼應該怎麼處理呢？

response.setContentType("application/json; charset=utf-8");
PrintWriter writer = null;
try {
writer = response.getWriter();
ObjectMapper mapper = new ObjectMapper();
ajaxJson ajaxJson = new AjaxJson();
ajaxJson .setSuccess(false);
ajaxJson .setMessage(code);
String errorMsg = mapper.writeValueAsString(ajaxJson);
writer.write(errorMsg);
writer.flush();
} catch (Exception ex) {
LOGGER.error("輸出錯誤響應資訊異常：" + ex.getMessage());
throw new RuntimeException("輸出錯誤響應資訊異常：" + ex.getMessage(), ex);
} finally {
if (writer != null) {
writer.close();
}
}
}