Oracle中使用了Union後的排序問題
阿新 • • 發佈:2019-01-25
最近使用SQL語句進行UNION查詢,驚奇的發現:SQL沒問題,UNION查詢也沒問題,都可以得到想要的結果,可是在對結果進行排序的時候,卻出問題了。
3.建立臨時表
1.UNION查詢沒問題
- SELECT `id`,`username`,`mobile`,`time`,id AS leader
- FROM `grouporder_leader`
- WHERE `courseid` = 21 AND `merchid` = 23 AND `status` = 1
- UNIONALL
- SELECT leadorderid,username,mobile,time,null
-
FROM `grouporder_partner`
- WHERE courseid=21 and status=1 and merchid=23
2.排序就出問題了
- SELECT `id`,`username`,`mobile`,`time`,id AS leader
- FROM `grouporder_leader`
- WHERE `courseid` = 21 AND `merchid` = 23 AND `status` = 1
- ORDERBYtimeDESC
- UNIONALL
- SELECT leadorderid,username,mobile,time,null
-
FROM `grouporder_partner`
- WHERE courseid=21 and status=1 and merchid=23
- ORDERBYtimeDESC
3.建立臨時表
使用類似於建立臨時表的方法儲存查詢結果,然後對臨時表進行查詢排序。
- SELECT id,username,mobile,time,leader
- FROM (SELECT `id`,`username`,`mobile`,`time`,id AS leader
-
FROM `grouporder_leader` WHERE `courseid` = 21 AND `merchid` = 23 AND
- UNIONALL
- SELECT leadorderid,username,mobile,time,null
- FROM `grouporder_partner` WHERE courseid=21 and status=1 and merchid=23
- )
- ORDERBYtimeDESC
不知道為什麼第3步中查詢依舊沒有,然後對UNION查詢的結果起個別名,然後再查詢排序就沒問題了。
- SELECT a.id,a.username,a.mobile,a.time,a.leader
- FROM (SELECT `id`,`username`,`mobile`,`time`,id AS leader
- FROM `grouporder_leader` WHERE `courseid` = 21 AND `merchid` = 23 AND `status` = 1
- UNIONALL
- SELECT leadorderid,username,mobile,time,null
- FROM `grouporder_partner` WHERE courseid=21 and status=1 and merchid=23
- ) AS a
- ORDERBYtimeDESC
查出來就好說了,再進行去重或者其他操作,也沒問題.
- SELECTDISTINCT a.id,a.username,a.mobile,FROM_UNIXTIME(a.time,'%Y/%m/%d') as _time,a.leader
- FROM (SELECT `id`,`username`,`mobile`,`time`,id AS leader
- FROM `grouporder_leader` WHERE `courseid` = 21 AND `merchid` = 23 AND `status` = 1
- UNIONALL
- SELECT leadorderid,username,mobile,time,null
- FROM `grouporder_partner` WHERE courseid=21 and status=1 and merchid=23
- ) AS a
- ORDERBYtimeDESC