方法一：

IQueryable<NewsContents專案> listNotice = null;

 listNotice = (from news in base.CabinData.NewsContents where news.FLAG == 1 select news).Distinct();

此種去除方法弊端：只要物件中有重複的欄位都會去除，會比對物件中所有的欄位。

方法二：

把linq查詢結果轉成list物件集合，再過濾去除重複項

 List<NewsContents專案> list = new List<NewsContents專案>();  // NewsContents專案 為實體類model

 list = (from news in base.CabinData.NewsContents where news.FLAG == 1 select news).Distinct();

List<NewsContents專案> listNotice = list.Distinct(new item_collection_DistinctBy_item1()).ToList();

 //去除重複項
        public class item_collection_DistinctBy_item1 : IEqualityComparer<Entity.NewsContents專案>
        {
            bool IEqualityComparer<Entity.NewsContents專案>.Equals(Entity.NewsContents專案 x, Entity.NewsContents專案 y)
            {
                if (x.Id == y.Id)
                {
                    return true;
                }
                else
                {
                    return false;
                }
            }

            int IEqualityComparer<Entity.NewsContents專案>.GetHashCode(Entity.NewsContents專案 obj)
            {
                return 0;
            }

        }

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